GRE Physics GR 1777, Problem 009 Solution

Posted on November 28, 2017January 1, 2021 by polaris

GRE Physics GR 1777 Problem Solution

009. Classical Mechanics (Kinematics)

Solution

$\frac{1}{2}Mv^2 = \frac{3}{2}kT$ ,
where $v$ is the root-mean-square speed of molecules in an ideal gas, $M$ is the mass of the molecule, and $T$ is the temperature of the system.

Since $k = \Big( \frac{n}{N} \Big) R$ ,
then $\frac{1}{2}Mv^2 = \frac{3}{2} \frac{n}{N} RT$ .

Therefore, $v = \sqrt{\frac{3RT}{M}}$ .

Answer

(D)

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