GRE GR 1777, Problem 017 Solution

17. Classical Mechanics (Stellar Dynamics)

In Keplar's Thrid law, the square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit.
T^2 \propto a^3
where T is the orbital period, and a is the semi-major axis of the planet.
For system 1 the radius of the orbit is a, and for system 2 the radius of the orbit is 4a.
The ratio of the period of system 1 and 2 can be described as
\Big( \frac{T_1}{T_2} \Big)^2 = \Big( \frac{a_1}{a_2} \Big)^3 = \Big( \frac{a}{4a} \Big)^3 = \Big( \frac{1}{64} \Big)
\frac{T_1}{T_2} = \frac{1}{8}

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